3.124 \(\int (a+b x)^5 (A+B x) \, dx\)

Optimal. Leaf size=38 \[ \frac {(a+b x)^6 (A b-a B)}{6 b^2}+\frac {B (a+b x)^7}{7 b^2} \]

[Out]

1/6*(A*b-B*a)*(b*x+a)^6/b^2+1/7*B*(b*x+a)^7/b^2

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Rubi [A]  time = 0.01, antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {43} \[ \frac {(a+b x)^6 (A b-a B)}{6 b^2}+\frac {B (a+b x)^7}{7 b^2} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*x)^5*(A + B*x),x]

[Out]

((A*b - a*B)*(a + b*x)^6)/(6*b^2) + (B*(a + b*x)^7)/(7*b^2)

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int (a+b x)^5 (A+B x) \, dx &=\int \left (\frac {(A b-a B) (a+b x)^5}{b}+\frac {B (a+b x)^6}{b}\right ) \, dx\\ &=\frac {(A b-a B) (a+b x)^6}{6 b^2}+\frac {B (a+b x)^7}{7 b^2}\\ \end {align*}

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Mathematica [B]  time = 0.02, size = 109, normalized size = 2.87 \[ a^5 A x+\frac {1}{2} a^4 x^2 (a B+5 A b)+\frac {5}{3} a^3 b x^3 (a B+2 A b)+\frac {5}{2} a^2 b^2 x^4 (a B+A b)+\frac {1}{6} b^4 x^6 (5 a B+A b)+a b^3 x^5 (2 a B+A b)+\frac {1}{7} b^5 B x^7 \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)^5*(A + B*x),x]

[Out]

a^5*A*x + (a^4*(5*A*b + a*B)*x^2)/2 + (5*a^3*b*(2*A*b + a*B)*x^3)/3 + (5*a^2*b^2*(A*b + a*B)*x^4)/2 + a*b^3*(A
*b + 2*a*B)*x^5 + (b^4*(A*b + 5*a*B)*x^6)/6 + (b^5*B*x^7)/7

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fricas [B]  time = 0.54, size = 121, normalized size = 3.18 \[ \frac {1}{7} x^{7} b^{5} B + \frac {5}{6} x^{6} b^{4} a B + \frac {1}{6} x^{6} b^{5} A + 2 x^{5} b^{3} a^{2} B + x^{5} b^{4} a A + \frac {5}{2} x^{4} b^{2} a^{3} B + \frac {5}{2} x^{4} b^{3} a^{2} A + \frac {5}{3} x^{3} b a^{4} B + \frac {10}{3} x^{3} b^{2} a^{3} A + \frac {1}{2} x^{2} a^{5} B + \frac {5}{2} x^{2} b a^{4} A + x a^{5} A \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^5*(B*x+A),x, algorithm="fricas")

[Out]

1/7*x^7*b^5*B + 5/6*x^6*b^4*a*B + 1/6*x^6*b^5*A + 2*x^5*b^3*a^2*B + x^5*b^4*a*A + 5/2*x^4*b^2*a^3*B + 5/2*x^4*
b^3*a^2*A + 5/3*x^3*b*a^4*B + 10/3*x^3*b^2*a^3*A + 1/2*x^2*a^5*B + 5/2*x^2*b*a^4*A + x*a^5*A

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giac [B]  time = 1.26, size = 121, normalized size = 3.18 \[ \frac {1}{7} \, B b^{5} x^{7} + \frac {5}{6} \, B a b^{4} x^{6} + \frac {1}{6} \, A b^{5} x^{6} + 2 \, B a^{2} b^{3} x^{5} + A a b^{4} x^{5} + \frac {5}{2} \, B a^{3} b^{2} x^{4} + \frac {5}{2} \, A a^{2} b^{3} x^{4} + \frac {5}{3} \, B a^{4} b x^{3} + \frac {10}{3} \, A a^{3} b^{2} x^{3} + \frac {1}{2} \, B a^{5} x^{2} + \frac {5}{2} \, A a^{4} b x^{2} + A a^{5} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^5*(B*x+A),x, algorithm="giac")

[Out]

1/7*B*b^5*x^7 + 5/6*B*a*b^4*x^6 + 1/6*A*b^5*x^6 + 2*B*a^2*b^3*x^5 + A*a*b^4*x^5 + 5/2*B*a^3*b^2*x^4 + 5/2*A*a^
2*b^3*x^4 + 5/3*B*a^4*b*x^3 + 10/3*A*a^3*b^2*x^3 + 1/2*B*a^5*x^2 + 5/2*A*a^4*b*x^2 + A*a^5*x

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maple [B]  time = 0.00, size = 121, normalized size = 3.18 \[ \frac {B \,b^{5} x^{7}}{7}+A \,a^{5} x +\frac {\left (b^{5} A +5 a \,b^{4} B \right ) x^{6}}{6}+\frac {\left (5 a \,b^{4} A +10 a^{2} b^{3} B \right ) x^{5}}{5}+\frac {\left (10 a^{2} b^{3} A +10 a^{3} b^{2} B \right ) x^{4}}{4}+\frac {\left (10 a^{3} b^{2} A +5 a^{4} b B \right ) x^{3}}{3}+\frac {\left (5 a^{4} b A +a^{5} B \right ) x^{2}}{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^5*(B*x+A),x)

[Out]

1/7*b^5*B*x^7+1/6*(A*b^5+5*B*a*b^4)*x^6+1/5*(5*A*a*b^4+10*B*a^2*b^3)*x^5+1/4*(10*A*a^2*b^3+10*B*a^3*b^2)*x^4+1
/3*(10*A*a^3*b^2+5*B*a^4*b)*x^3+1/2*(5*A*a^4*b+B*a^5)*x^2+a^5*A*x

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maxima [B]  time = 1.06, size = 115, normalized size = 3.03 \[ \frac {1}{7} \, B b^{5} x^{7} + A a^{5} x + \frac {1}{6} \, {\left (5 \, B a b^{4} + A b^{5}\right )} x^{6} + {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} x^{5} + \frac {5}{2} \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} x^{4} + \frac {5}{3} \, {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} x^{3} + \frac {1}{2} \, {\left (B a^{5} + 5 \, A a^{4} b\right )} x^{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^5*(B*x+A),x, algorithm="maxima")

[Out]

1/7*B*b^5*x^7 + A*a^5*x + 1/6*(5*B*a*b^4 + A*b^5)*x^6 + (2*B*a^2*b^3 + A*a*b^4)*x^5 + 5/2*(B*a^3*b^2 + A*a^2*b
^3)*x^4 + 5/3*(B*a^4*b + 2*A*a^3*b^2)*x^3 + 1/2*(B*a^5 + 5*A*a^4*b)*x^2

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mupad [B]  time = 0.06, size = 103, normalized size = 2.71 \[ x^2\,\left (\frac {B\,a^5}{2}+\frac {5\,A\,b\,a^4}{2}\right )+x^6\,\left (\frac {A\,b^5}{6}+\frac {5\,B\,a\,b^4}{6}\right )+\frac {B\,b^5\,x^7}{7}+A\,a^5\,x+\frac {5\,a^2\,b^2\,x^4\,\left (A\,b+B\,a\right )}{2}+\frac {5\,a^3\,b\,x^3\,\left (2\,A\,b+B\,a\right )}{3}+a\,b^3\,x^5\,\left (A\,b+2\,B\,a\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((A + B*x)*(a + b*x)^5,x)

[Out]

x^2*((B*a^5)/2 + (5*A*a^4*b)/2) + x^6*((A*b^5)/6 + (5*B*a*b^4)/6) + (B*b^5*x^7)/7 + A*a^5*x + (5*a^2*b^2*x^4*(
A*b + B*a))/2 + (5*a^3*b*x^3*(2*A*b + B*a))/3 + a*b^3*x^5*(A*b + 2*B*a)

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sympy [B]  time = 0.10, size = 129, normalized size = 3.39 \[ A a^{5} x + \frac {B b^{5} x^{7}}{7} + x^{6} \left (\frac {A b^{5}}{6} + \frac {5 B a b^{4}}{6}\right ) + x^{5} \left (A a b^{4} + 2 B a^{2} b^{3}\right ) + x^{4} \left (\frac {5 A a^{2} b^{3}}{2} + \frac {5 B a^{3} b^{2}}{2}\right ) + x^{3} \left (\frac {10 A a^{3} b^{2}}{3} + \frac {5 B a^{4} b}{3}\right ) + x^{2} \left (\frac {5 A a^{4} b}{2} + \frac {B a^{5}}{2}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**5*(B*x+A),x)

[Out]

A*a**5*x + B*b**5*x**7/7 + x**6*(A*b**5/6 + 5*B*a*b**4/6) + x**5*(A*a*b**4 + 2*B*a**2*b**3) + x**4*(5*A*a**2*b
**3/2 + 5*B*a**3*b**2/2) + x**3*(10*A*a**3*b**2/3 + 5*B*a**4*b/3) + x**2*(5*A*a**4*b/2 + B*a**5/2)

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